How many digits can be taken in place of x so that the given number is divisible by 3 ?

 

Divisibility Rule Based Questions

2378x83 

How many digits can be taken in place of x so that the given number is divisible by 3 ?

Explanation 2+3+7+8+x+8+3=31+x should divisible by 3

                      Probale value of x

If X=0 31+x=31

X=1    31+x=32

X=2    31+x=33

X=3   31+x=34

X=4   31+x=35

X=5   31+x=36

X=6   31+x=37

X=7   31+x=38

X=8   31+x=39

X=9   31+x=40

Since out of 31,32,33,34,35,36,37,38,39,40  33,36,39 divisible by 3 therefore 3 digit can be taken in place of x.

Quicker: Since 31 is not divisible by 3 therefore maximum therefore 3 digit can be taken in place of x.

3378x93 

How many digits can be taken in place of x so that the given number is divisible by 3 ?

Explanation 3+3+7+8+x+9+3=33+x should divisible by 3

Probale value of x

If X=0 33+x=33

X=1    33+x=34

X=2    33+x=35

X=3   33+x=36

X=4   33+x=37

X=5   33+x=38

X=6   33+x=39

X=7   33+x=40

X=8   33+x=41

X=9   33+x=42

Since Out of 33,34,35,36,37,38,39,40,41,42  33,36,39,42 is divisible by 3

Quicker: Since 33 is  divisible by 3 therefore maximum therefore 4 digit can be taken in place of x.

Example:

5368x24 

How many digits can be taken in place of x so that the given number is divisible by 3 ?

Quicker- 5+3+6+8+x+2+4=28+x

Here 28 is not divisible by 3 therefore number of digit can be taken in place of X is 3.

30,33,36